Mehapatel

Hatch-Slack (C4) Cycle
C4 plants like maize, sugarcane; pearl millet, etc. have evolved a wonderful mechanism to avoid photorespiration.
In these plants three or 2 types of photosynthetic cells namely mesophyll cells and bundle sheath cells are present. The bundle sheath cells are arranged in a wreath like manner, thus calling them as kranz anatomy.
One more speciality of C4 plants is that they contain dimorphic chloroplasts, that is chloroplasts in bundle-sheath cells are agranal. The presence of two types of cells allows the occurrence of light reactions and carbon reactions separately.

Since, tangents drawn from an exterior point to a circle are equal in length.
∴ AP = AS    ...(i)BP = BQ    ...(ii)CR = CQ    ...(iii)and DR = DS    ...(iv)Adding (i), (ii), (iii) and (iv), we getAP + BP + CR + DR = AS + BQ + CQ + DS⇒ (AP + BP) + (CR + DR)= (AS + DS) + (BQ + CQ)⇒ AB + CD = AD + BCHence, AB + CD = BC + DA.

According to question, Required distance  =                                 

Wechsler defined intelligence as the global and aggregate capacity of an individual to think rationally, act purposefully and to deal effectively with his / her environment.PASS Model of Intelligence developed by J P Dass, Jack Naglieri & Kirby in 1994.This model is comprised of the following-P – PLANNINGA – AROUSAL / ATTENTIONS – SIMULTANEOUSS – SUCCESSIVEPlanning: After the information is attended to and processed, planning is activated. For example, planning a time schedule for gyming.Arousal/Attention: An optimal level of arousal focuses our attention to the relevant aspects of a problem.

Given that,Mass of the copper block, m = 2.5 kg = 2500 gRise in the temperature of the copper block, Δθ = 500°CSpecific heat of copper, C = 0.39 J g–1 °C–1Heat of fusion of water, L = 335 J g–1The maximum heat the copper block can lose, Q = mCΔθ                                                                = 2500 × 0.39 × 500                                                                 = 487500 J Let m1 g be the amount of ice that melts when the copper block is placed on the ice block. The heat gained by the melted ice, Q = m1L ∴                      m1 = Q / L                            

In right ∆ABC, by Pythagoras Theorem.AC2 = BC2 + AB2...(i)Similarly, in rt. ∆ABD,AD2 = BD2 + AB2                                                                                                     ...(ii)From (i) and (ii), we  get                         

The equation of parabola is y2 = 4 a (x-1)    ...(1)When y = 4 a , from (1) 16 a2 = 4 a (x-1)⇒ x - 1 = 4 a ⇒ x = 4 a + 1                        

Using Gauss theorem,

Given, length of the elctric dipole = 4cm=4×10-2 mangle made with the elctric field-θ=60∘Torque experienced by the dipole-τ = 43 Nmcharge on the dipole-q=±8nC = ±8×10-9 Ci) magnitude of Electric field-E                          τ= pE sinθ    = q × 2a × E sinθ     ⇒  43 = 8×10-9 × 4×10-2 × E × sin 60°    ⇒       E = 43×232 ×10-11×3    = 14×1011     = 2.5 × 1010 NC-1(ii) magnitude of potential energy of the dipole  U = -pE cos θ    = -q×2a×E cos θ    =-8×10-9×2×10-2×2.5×1010 cos 60°= - 2J.

TEXT = "GREAT"
DAY = ""
for T in range (0,7):
print TEXT [T]
print T, TEXT
The range(0,7) will give a runtime error as the index is out of range. It should be a range(0,6).

(i) Glucose reacts with hydroxylamine to form glucose oxime Glucose reacts with hydrogen cyanide to form cyanohydrin.These reaction confirm the presence of a carbonyl group (>C=O) in glucose.ii) Glucose gets oxidised to six carbon carboxylic acid (gluconic acid) on reaction with a mild oxidising agent like bromine water. This indicates that the carbonyl group is present as an aldehydic group.
 

Hydraulic lift is a machine used to multiply the force and it is based on Pascal law.
Hydraulic lift consists of two cylinders of different cross-sectional areas connected with a pipe. The cylinders are filled with incompressible liquid and frictionless pistons are fitted in both the cylinders as shown in figure.Let a and A be the area of cross-section of smaller piston and bigger piston respectively. The load to be lifted is placed on bigger cross-section and effort is applied on smaller piston. Let a force f be applied on the smaller piston. The pressure exerted by f on piston is,According

प्राथमिक गतिविधियाँ - प्राथमिक गतिविधियाँ वे होती हैं जो प्रत्यक्ष रूप से पर्यावरण पर निर्भर हैं क्योंकि ये पृथ्वी के संसाधनों जैसे भूमि, जल, वनस्पति, भवन-निर्माण सामग्री एवं खनिजों के उपयोग के विषय में बतलाती हैं। इस प्रकार की क्रियाओं के अंतर्गत आखेट, भोजन, भोजन संग्रह, पशुचारण, मछली पकड़ना, वनों से लकड़ी काटना, कृषि एवं खनन कार्य शामिल किए जाते हैं।द्वितीयक गतिविधियाँ - द्वितीयक गतिविधियों द्वारा प्राकृतिक संसाधनों का मूल्य बढ़ जाता है। प्रकृति में पाए जाने वाले कच्चे माल का रूप बदलकर ये उसे मूल्यवान बना देती हैं। जैसे कपास से वस्त्र बनाना, लौह अयस्क से लौह-इस्पात बनाना । इस प्रकार निर्मित वस

Using mirror formula, 1f = 1v1 +1u-115 = 1v1 +1u⇒1v1 = 1-15 + 140∴ = - 24 cmWhen object is displaced by 20 cm towards mirror Now, u2 = -20So, 1f = 1v2  + 1u21-15 = 1v2 - 120⇒ 1v2 = 120-115Therefore, image shifts away from mirror by  = 60-24 = 36 cm 

Current flowing in the series combination is same for all appliances. Also,             Power P = I2RSo, the resistance offered by the 500 W bulb will be more and less amount of current will pass through it. Hence, heat produced by the 100 W bulb will be more and it will glow brighter as compared to the 500 W bulb.

MNCs are playing a major role in the globalisation process.
(i) MNCs is not only selling its finished products globally, but more important, the goods and services are produced globally.
 (ii) The production process is divided into small parts and spread out across the global.
(iii) The result of greater foreign investment and greater foreign trade has been greater integration of production and markets across countries.
(iv) More and more goods and services, investments and technology are moving between countries.
 (v) The technology has made much faster delivery of goods across long dis

Apply Kepler s law of area fo planetary motion.The line joining the sun to the planet sweeps out equal areas time interval ie, areal velocity is constant.

Once Saint Peter stopped by an old lady s cottage because he was feeling hungry and weak after the day s fasting. The lady was baking cakes on the hearth. Since he was weak with fasting, he asked her for a cake from her store of cakes. 
The selfish lady tried to bake small cakes but each time they seemed too big for her to give away. Finally, she baked one that was as thin as a wafer. Unable to part with it too, she put it on a shelf and did not give any cake to the Saint.
Saint Peter was very angry with her behaviour and said she was too selfish to live as a human and have food, shelter an

The commission of enquiry decided to make refunds to the peasants.Gandhi asked for 50%. But the representative of planters offered to refund to the extent of 25%. In order to break the deadlock, Gandhiji agreed to 25 percent refund to the farmers.For Gandhi, it was not the money but the principles that were of utmost importance. In his belief, the submission of British landlords was more significant than the percentage of refund. He wanted the poor farmers to realise that they too had rights and that they need not really live in fear of the British landlords.The conflict between the British p

Before the collision, the rod is at rest and bullet is moving with velocity u at a distance 0.8L. Therefore angular momentum of system before impact is,Bullet after hitting gets embedded into the rod.Let  be the angular velocity of the system after impact. The angular momentum of system after impact is, Using the law of conservation of momentum This is the angular velocity of the system after the impact.